Question

The half-life of silicon-32 is 710 years. If 40 grams is present now, how much will be present in 800 years

Answer 1

18 g of silicon-32 will be present in 800 years.

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and it's given by

                              $N(t) = N_0 (\frac{1}{2}) ^\frac{t}{t_\frac{1}{2} }$

where,

$N(t) =$ quantity of the substance remaining

$N_0 =$  the initial quantity of the substance

$t =$  time elapsed

$t_1_/_2 =$ the half-life of the substance

From the given information we know:

The initial quantity of silicon-32 is 40 g.

The time elapsed is 800 years.

The half-life of silicone-32 is 710 years.

So, using the calculation above, we can determine how much silicon-32 is left.

                  $N(t) = 40 (\frac{1}{2}) ^\frac{800}{710} \\N(t) = 40 (\frac{1}{2}) ^\frac{80}{71} \\\\N(t) = 18 g$

Therefore,18 g of silicon-32 will be present in 800 years.

Learn more about half-life here:

brainly.com/question/25750315

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