Answer:
According to the chart, the period and string length are not the same. Regardless of string length. The chart says that "period = seconds 10"
Explanation:
So for example in Trial 1. The period equaled 8.7, so in turn you would times 8.7 by 10 and get 87. Which is not equal to the string length. For they are also measured in two different measurements.
If the solute is properly distributed in the given volume, there are 2.642 g of (NH4)2SO4 per 10 mL. For the new solution, divide the 2.642 g by the molar mass of the compound. The answer is 0.02 moles. Then, divide this by the new volume, 50 mL or 0.05 L. The concentration of the new solution is 0.4 M.
Answer:
You can find in the given attachemnet
N = M x V
n = 2.5 x 5.0
n = 12.5 moles of C6H12O6
1 electron has charge =1.602* 10⁻¹⁹ C
1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol
One ion Co²⁺ takes 2e⁻ to become Co⁰.
1 mol of Co²⁺ ions take 2 mole of e⁻ to become Co⁰, so
0.30 mol Co²⁺ ions take mole of 0.60 mol e⁻ to become Co⁰
9.64*10⁴(C/1mol) *0.60 (mol)≈ 5.8 *10⁴ Coulombs.
Correct answer is C
