2 years ago

For the oxidation of ammonia

Chemistry

1 answer:

OverLord2011 [107]2 years ago

5 0

The answer is 0.405 M/s

- (1/3) d[O2]/dt = 1/2 d[N2]/dt

- d[O2]/dt = 3/2 d[N2]/dt

- d[O2]/dt = 3/2 × 0.27

- d[O2]/dt = 0.405 mol L^(-1) s^(-1)

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