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3 years ago

How does the electrical force relate to the distance between two charged objects?

Chemistry

2 answers:

vivado [14]3 years ago

6 0

Answer

It is inversely proportional to the square of the distance

Explanation

This is the inverse square law , where in electrostatics, the electric force between two charged objects is inversely connected to the distance of separation between the two objects. This is to mean an increase in separation distance between objects will cause a decrease in the force of attraction between the objects.

77julia77 [94]3 years ago

5 0

Answer:

The correct answer option is 'It is inversely proportional to the square of the distance.'

Explanation:

The electrical force is inversely proportional to the square of the distance.

The relation of the electrical force to the distance between the two charged objects is given by the Coloumb's law which states that:

$ef=k\frac{q_1*q_2}{r^2}$

where $ef$ is the electrical force, $q_1$ and $q_2$ are the two charges which are separated by the distance $r$ .

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A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.

solniwko [45]

The missing question is:

What is the percent efficiency of the laser in converting electrical power to light?

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

$Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J$

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

$E = \frac{h \times c }{\lambda }$

where,

h: Planck's constant

c: speed of light

$E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J$

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

$\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J$

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

$Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%$

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

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3 years ago

Why does it take so much heat and pressure to create helium and other elements?

ehidna [41]

Answer:

To break down the nucleus of an atom

Explanation:

Remember to change from one element to another, is necessary to add protons, neutrons and electrons,in most of the cases.

The take an electron from an atom you need certain energy, but they are in the outside part of the atom so is not as much energy as the one is necessary to take one neutron or proton from the inside part of an atom.

In this way, is a must to have a combination of pressure and heat to destabilize an atom and take some of this subatomic particles.

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3 years ago

What is the term that describe two species living together

Sergeu [11.5K]

I think it is Symbiosis. But I dont know how to explain it

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3 years ago

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Nitrous oxide (N2O) is used as an anesthetic (laughing gas) and in aerosol cans to produce whipped cream. It is also a potent gr

scZoUnD [109]

Answer:

five half lives

Explanation:

Half-life is the time required for a quantity to reduce to half of its initial value.

How many half lives it would take to reach 3.13% form 100% of it's initial concentration:

100% - 50% : First Half life

50% - 25%: Second Half life

25% - 12.5%: Third Half life

12.5% - 6.25%: Fourth Half life

6.25% - 3.125%: Fifth Half life

This means it would take five half lives to get to 3.125% (≈ 3.13%) of it's original concentration.

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Pressure is inversely related to?

jekas [21]

Pressure is inversely related to temperature

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