Question

PLSSS C= 7D%7D" id="TexFormula1" title="\frac{12^{3} . 6^{5} }{9^{4} . 2^{10}}" alt="\frac{12^{3} . 6^{5} }{9^{4} . 2^{10}}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

2

Step-by-step explanation:

The trick here is to reduce each of the bases to lowest form first

$12 = 3.4 = 3 .2.2 = 3.2^{2}\\12^{3} = (3.2^{2} )^{3} = 3^{3}2^{6} \\6 = 3.2\\6^{5} = (3.2)^{5} = 3^{5} .2^{5} \\\\Numerator = 3^32^63^52^5 = 3^82^{11}\\Denominator computation\\9 = 3^2\\9^{4} = (3^{2} )^4 = 3^{8} \\Denominator = 3^82^{10} \\\\\frac{Numerator}{Denominator } =\frac{{3^8}{2^{11} }}{3^82^{10}} = \frac{2^{11}} {2^{10}} = 2^1 = 2$