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shtirl [24]
2 years ago
9

Sand will be placed under a circular pool with a diameter of 20 feet. The sand depth should be 2 inches. How many cubic feet of

sand are needed?
Mathematics
1 answer:
JulsSmile [24]2 years ago
7 0

you need 628 square feet of sand.

<h3>How many cubic feets of sand are needed?</h3>

Here we need to find the volume of the sand needed.

The volume filled with sand will be a cylinder of diameter of 20ft, and a height of 2 inches.

First, the radius is half of the diameter, then:

R = 20ft/2 =10ft

Remember that:

1ft= 12in

Then:

R = 10ft = 10*(12 in) = 120 in

And remember that the volume of a cylinder of radius R and height H is:

V  = pi*R^2*H

Where pi = 3.14

Then we have:

V = 3.14*(120 in)^2*2in = 90,432 in^2

To get that in feets, we need to divide by 12 squared, then:

90,432 in^2 = 90,432ft^2/(12^2)  = 628 ft^2

So you need 628 square feet of sand.

If you want to learn more about volumes:

brainly.com/question/1972490

#SPJ1

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A meal coats $16.64. What's the total cost with a 15% tip?​
kotegsom [21]

Answer:

$19.136

Step-by-step explanation:

if 100% ----> $16.64

then 115% ----> $19.136

hope this helps :)

5 0
2 years ago
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250 divided by 10 squared equals?
navik [9.2K]
250 divided by 10 squared is 2.5
4 0
3 years ago
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WILL MARK AS BRAINLIEST PLEASE HELP!!!
neonofarm [45]

Step-by-step explanation:

2x = y-10

Rewrite as: 2x + 10 = y

Therefore:

2x+10 = y

2x +7 = 2y

Subtract the equations:

 2x + 10 = y

- 2x + 7 = 2y

______________

          3 = -y

Therefore y = -3

Substiture y = -3 into the second equation:

2x + 7 = 2(-3)

2x + 7 = -6

2x = -13

x= -6.5

Answer : (-6.5, -3)

3 0
3 years ago
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What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
3 years ago
Answer the question below.
gregori [183]

Answer:

1/3

Step-by-step explanation:

4 0
3 years ago
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