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Luden [163]
2 years ago
14

Jacy earns 14$ each second. He earns 14$ each second for 18 years. How much money would he have if he saved up the money?

Mathematics
1 answer:
Ratling [72]2 years ago
7 0

they deleted my answer and they wont tell me why- let me try again

<u><em>answer:</em></u> jacy would earn a total of $7,952,345,352 if he saved up for a total of 18 years.

<u><em>explanation:</em></u>

the total of seconds among 18 years: <em>568,024,668 seconds.</em>

we now take the 568,024,668 and multiply it by 14.

<em>our final answer is </em><em>$7,952,345,352.</em>

i dont know if this is a genuine question or not but here-

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What is the following simplified product? Assume x&gt;0.
tensa zangetsu [6.8K]

Answer:

24x ^{3}  \sqrt{5 - 4x ^{3} } \sqrt{10x}

8 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
I need to know how to solve this equation for x
mel-nik [20]
I hope this helps. X is equal to 4 and -9

5 0
4 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
Need help thank you very much
Zarrin [17]

Answer:

a)  -    9/2   or   -0,45

b)  -   3/5    or -0,6

c)   -4

d)  1

e)  -2

d)  0

Step-by-step explanation:

4 0
3 years ago
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