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2 years ago

A couple quick algebra 1 questions for 50 points!

Mathematics

1 answer:

kirill [66]2 years ago

6 0

All the relevant transformations are as shown in the explanations below.

<h3>How to Interpret Transformations?</h3>

We are given the original function as y = x and told the transformation is as follows;

1) y = x + 5; This means that the function was shifted 5 units to the left.

2) y = ³/₈x; This means that the function was vertically stretched by a scale factor of ³/₈.

3) y = -x - 2 or y = -(x + 2); This means that the function was first shifted by 2 units to the left before being reflected over the x-axis.

4) y = 6x + 1; This means that the function was stretched by a factor of 6 and then shifted 1 unit to the left.

5) y = x - 11; This means that the function was shifted 11 units to the right.

6) y = 8x; This means that the function was vertically stretched by a scale factor of 8.

7) y = -1/3x; This means that the function was horizontally stretched by a scale factor of 1/3.

Read more about Transformations at; brainly.com/question/4289712

#SPJ1

You might be interested in

−76 = −0.8k <br><br> k =<br><br> What number represents k

Over [174]

Answer:

k= 95

Step-by-step explanation:

-76=-0.8k

-76/-0.8=k

95=k

k= 95

8 0

3 years ago

I need this asap. Would appreciate for y’all help

steposvetlana [31]

Answer:

-3/2, -1

Step-by-step explanation:

Each coordinate contains one $x$ value and one $y$ value, $(x,y)$ .

If we work out the midpoint of each of these individually, it makes it much easier to find the midpoint of the line.

Let's take the $x$ values first. Our first $x$ value is -4 and our second $x$ value is 1. Imagine the integers between -4 and 1 laid out in a sequence:

$-4, -3, -2, -1, 0, 1$

If you take the middle value of this sequence, you get the midpoint of the $x$ values.

In this case, the middle is between values -2 and -1, leaving us with a midpoint of -1.5. This as a fraction is $-\frac{3}{2}$ .

Now let's look at the $y$ values. Our first $y$ value is 2 and our second $y$ value is -4. Again, let's imagine those numbers laid out in a sequence:

$2, 1, 0, -1, -2, -3, -4$

Here, the middle of these values is -1, and this is the midpoint of the $y$ values.

So if we put these two values in a coordinate, we get the midpoint of the line.

In this case, we get $(-\frac{3}{2} ,-1)$ .

5 0

2 years ago

Xander says that it is not possible to draw a quadrilateral that is not a parallelogram and not a trapezoid. Devin says it is po

Olenka [21]

A good place to start for this question is to define the properties of the geometric terms you are given.

Quadrilaterals have four straight sides.

Parallelograms are quadrilaterals that have two pairs of parallel sides. The opposite sides and opposite angles are congruent. Squares, rectangles, and rhombuses are examples of parallelograms.

Trapezoids are also quadrilaterals. They have only one pair of parallel sides.

So we're looking to see if there are any four-sided shapes that can be made with no parallel sides. The attached picture shows an example of a quadrilateral that is not a parallelogram and is not a trapezoid. Based on these properties of polygons, the correct answer is B.