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Lelechka [254]
3 years ago
13

Help this is extremely confusing

Mathematics
1 answer:
Sati [7]3 years ago
4 0

Answer:

x = 10

Step-by-step explanation:

With UW extended to point X, then

∠VWX is an external angle of the triangle.

The external angle of a triangle is equal to the sum of the 2 opposite interior angles, that is

∠VWX = ∠WUV + ∠UVX ← substitute values

6x - 19 = 3x + 3 + x - 2, that is

6x - 19 = 4x + 1 (subtract 4x from both sides )

2x - 19 = 1 ( add 19 to both sides )

2x = 20 ( divide both sides by 2 )

x = 10

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Is 3/10 equivalent to 2/5 please tell me the right answer
aev [14]
3 divided by 10 is 0.3

2 divided by 5 is 0.4.

They are not equivalent.
8 0
3 years ago
Zach read a book for 10 minutes every weekend in the first month, 20 minutes in the second month, 40 minutes in the third month,
san4es73 [151]
Victoria's method is linear because the number of minutes increase by an equal number (15) every month.

Workings in the attachments below. The green line is the function that has been set up for Victoria. The lines that form a curved looking graph belong to the function that was set up for Zach.

8 0
3 years ago
What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis
Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)  

Step-by-step explanation:

\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

4 0
3 years ago
Read 2 more answers
Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side
svp [43]
A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
      = (7 - 5) ÷ 2
      = 2 ÷ 2
      = 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²) 
      = √(5² - 1²)
      = √(25 - 1)
      = √24
      = 2√6

Last, we have all the information needed in order to calculate the area by the formula:

A =  \frac{(AB + CD)DH}{2}

A = (7 + 5) × 2√6 ÷ 2
   = 12√6

The area of the regular trapezoid is 12√6 square units.

7 0
3 years ago
Please solve (-3×+15)+(-3×+2)
koban [17]
(-3x + 15) + (-3x + 2)
Simplify by combining like terms.
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-6x + 17
3 0
3 years ago
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