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1 year ago

13

kelvin pumped 15.2 gallons of gas into his car. if he paid 59.13 for the total amount of gas, what was the rate per gallon that

kelvin paid

1 answer:

drek231 [11]1 year ago

7 0

Answer:

3.89

Step-by-step explanation:

if 15.2 gallons cost 59.13.What about 1

then we just divide 59.13 by 15.2 to get the cost of 1 gallon

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If y = 3ab + 2b3, what is y when a = 1 and b = 2

Dominik [7]

Answer: The required value of y is 22.

Step-by-step explanation: We are given the following function of a and b :

$y=3ab+2b^3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the value of y when a = 1 and b = 2.

To find the required value of y, we need to substitute the values of a and b in equation (i).

From (i), we get

$y=3\times1\times2+2\times2^3=6+16=22.$

Thus, the required value of y is 22.

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3 years ago

Square RSTU is inscribed in circle P. Given the coordinates for the vertices of the square, find the equation of circle P.

svlad2 [7]

Answer:

$(x-2)^2+y^2=20$

Step-by-step explanation:

We want to find the equation of a circle P, and we know that the square RSTU is inscribed in the circle, this means that if we replace the points:

R(0,4) S(6,2) T(4,-4) and U(-2,-2) the equation must be verified.

Then, we have to replace the points in each option to see which one is the correct answer.

Option A: $(x-2)^2+y^2=68$

R(0,4):

$(x-2)^2+y^2=68\\(0-2)^2+4^2=68\\(-2)^2+16=68\\4+16=68\\20\neq 68$

We can see that R doesn't belong to the equation of the circle.

We could replace the rest of the points in the equation, but since we already know that R does not belong to the circle, we already know that it is not the right option.

Option B: $(x+2)^2+y^2=20$

R(0,4):

$(x+2)^2+y^2=20\\(0+2)^2+4^2=20\\2^2+4^2=20\\4+16=20\\20=20$

The point R(0,4) verifies the equation.

S(6,2):

$(x+2)^2+y^2=20\\(6+2)^2+2^2=20\\8^2+4^2=20\\64+16=20\\80\neq 20$

The point S doesn't belong to the equation of the circle, then we already know that this isn't the correct option.

Option C: $(x-2)^2+y^2=20$

R(0,4):

$(x-2)^2+y^2=20\\(0-2)^2+4^2=20\\(-2)^2+16=20\\4+16=20\\20=20$

The point R verifies the equation.

S(6,2):

$(x-2)^2+y^2=20\\(6-2)^2+2^2=20\\4^2+4=20\\16+4=20\\20=20$

The point S verifies the equation.

T(4,-4):

$(x-2)^2+y^2=20\\(4-2)^2+(-4)^2=20\\2^2+16=20\\4+16=20\\20=20$

The point T verifies the equation.

U(-2,-2):

$(x-2)^2+y^2=20\\(-2-2)^2+(-2)^2=20\\(-4)^2+4=20\\16+4=20\\20=20$

The point U verifies the equation.

<em>We can see that the four points RSTU verifies the equation. This means that the square RSTU is inscribed in circle P whose equation is: </em> $(x-2)^2+y^2=20$

<em>We can see that the graph of the equation verifies the answer.</em>

3 0

4 years ago

0.333... as a fraction it’s repeating fraction and 0.666 as a repeating fraction

andre [41]

Answer:

0.333 is 1/3

0.666 is 2/3

Step-by-step explanation:

I used my head but you can use a calculator too.

7 0

3 years ago

Read 2 more answers

The drawing below is an example of what kind of perspective?

Lera25 [3.4K]

This appears to be 2 two point perspective.

3 0

4 years ago

9/3 *[(18-10)-2^2]<br><br><br>36<br><br>12<br><br>0.25<br><br>0.75

poizon [28]

Answer:

12

Step-by-step explanation:

Use the PEMDAS

there is a parenthesis and exponents

9/3{(8) - 4)}

Multiply and divide 9/3= 3

Also subtract 8-4 = 4

3{8-4}

3(4)= 12

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3 years ago