1

Mathematics

2 answers:

nasty-shy [4]2 years ago

5 0

Answer:

hope this helps :)

zysi [14]2 years ago

3 0

Answer:

Step-by-step explanation:

to find the zeros, equate f(x) to zero, that is

(x - 7)(x + 8) = 0

equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 8 = 0 ⇒ x = - 8

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Name: 1. Label the axes. 2. Graph: A(-3, 0) B(-2, 4) C(1, -1) Draw AABC in blue. 3. Rotate AABC 90° clockwise to create AA'B'C'

nikklg [1K]

Answer:

its B because

Step-by-step explanation:

Simplifying

41n(7x) = 8

Remove parenthesis around (7x)

41n * 7x = 8

Reorder the terms for easier multiplication:

41 * 7n * x = 8

Multiply 41 * 7

287n * x = 8

Multiply n * x

287nx = 8

Solving

287nx = 8

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Divide each side by '287x'.

n = 0.02787456446x-1

Simplifying

n = 0.02787456446x-1

3 0

2 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$