Instance
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Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512
This is a java program with a class called Sum1.
Explanation:
While loop is used to add 10 number.
import java.util.Scanner;
public class Sum 1
{
public static void main(String args[])
{
int number, count, sum = 0;
Scanner s = new Scanner(System.in);
System.out.print("Enter the number:");
number = s.nextInt();
while(number > 0)
{
count = number % 10;
sum = sum + n;
number = number / 10;
}
System.out.println("Sum of Digits:"+sum);
}
}
Answer:
C is the answer!
Explanation:
A hard drive contains your operating system which can include your settings and preferences that you included in your device. But it mostly is a storage device so we know it WOULD NOT BE (B.
WOULD NOT BE D beacause powering it back on wouldnt do anything but bring you back to the start.
WOULD NOT BE A beacuse when taking out the battery then putting it back in would just be like turning it off then back on beacuse that just hold the power to a device.
IT WOULD BE C, C IS THE ANSWER beacuse a CMOS batttery contains the main system settings and also contains information so i think C would be the best answer for this choice.
Hope this helps!
xx <3
