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2 years ago

Which principle suggests that specific single responsibility interfaces are better than one general purpose interface?

Computers and Technology

1 answer:

ElenaW [278]2 years ago

8 0

Answer:Interface segregation principle

Explanation: Interface-segregation principle (ISP) is amongst the major principles of the object-oriented design which describes that none of the users/clients can be forced for indulging and depending on the unknown methods or methods that they don't have knowledge about.

It functions by making the interfaces visible to the user that specifically fascinates them and keeping other smaller interfaces.Interfaces are made by splitting process and making the small interfaces from them.

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Stopping the car. Do not continue driving if your tire has failed or blown out. After you stop the car, call for roadside assistance. Remember, safety first when you're driving!

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What are some industries of aerodynamics and hydrodynamics? explain each one in detail.

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Aerodynamic- Wind turbine, computational fluid dynamics, and Wind power

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2 years ago

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(a) How many locations of memory can you address with 12-bit memory address? (b) How many bits are required to address a 2-Mega-

I am Lyosha [343]

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Let,

The address of 1-bit memory to add in 2 location:

$\to \frac{0}{1} =2^1 \ (\frac{m}{m} \ location)$

The address of 2-bit memory to add in 4 location:

$\to \frac{\frac{00}{01}}{\frac{10}{11}} =2^2 \ (\frac{m}{m} \ location)$

similarly,

Complete 'n'-bit memory address' location number is = $2^n.$ Here, 12-bit memory address, i.e. n = 12, hence the numeral. of the addressable locations of the memory:

$= 2^n \\\\ = 2^{12} \\\\ = 4096$

In point b:

$\to Let \ Mega= 10^6$

$=10^3\times 10^3\\\\= 2^{10} \times 2^{10}$

So,

$\to 2 \ Mega =2 \times 2^{20}$

$= 2^1 \times 2^{20}\\\\= 2^{21}$

The memory position for ' $2^n$ ' could be 'n' m bits'

It can use $2^{21}$ bits to address the memory location of 21.

That is to say, the 2-mega-location memory needs '21' bits.

Memory Length = 21 bit Address

In point c:

$i^{th}$ element array addresses are given by:

$\to address [i] = B+w \times (i-LB)$

$_{where}, \\\\B = \text {Base address}\\w= \text{size of the element}\\L B = \text{lower array bound}$

$\to B=\$ 52\\\to w= 4 byte\\ \to L B= 0\\\to address = 10$

$\to address [10] = \$ 52 + 4 \times (10-0)\\$

$= \$ 52 + 40 \ bytes\\$

1 term is 4 bytes in 'MIPS,' that is:

$= \$ 52 + 10 \ words\\\\ = \$ 512$

In point d:

$\to base \ address = \$ t 5$

When MIPS is 1 word which equals to 32 bit :

In Unicode, its value is = 2 byte

In ASCII code its value is = 1 byte

both sizes are < 4 byte

Calculating address:

$\to address [5] = \$ t5 + 4 \times (5-0)\\$

$= \$ t5 + 4 \times 5\\ \\ = \$ t5 + 20 \\\\= \$ t5 + 20 \ bytes \\\\= \$ t5 + 5 \ words \\\\= \$ t 10 \ words \\\\$

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3 years ago

You've determined that your email program, Outlook, is not working, and your

Tanzania [10]

You've determined that your email program, Outlook, is not working, and your manager tells you to reboot your email program Go and restart outlook. If it begins offevolved and works fine, then Outlook is fine, if now no longer, continue to the following approach to troubleshoot.

<h3>Why is my Outlook Email now no longer working?</h3>

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Go and restart outlook. If it begins offevolved and works fine, then Outlook is fine, if now no longer, continue to the following approach to troubleshoot. Press the Windows key and press “r” to your keyboard and sort outlook.exe /reset navpane in the “Run” conversation box.
Press “Enter” to run OutlookWhile the using of Microsoft Outlook, you may have come upon several forms of mistakes which restrict you from getting access to it completely.
And one of the maximum encountered mistakes is ‘Outlook isn't closing’, even after clicking the go out button a couple of times.