Answer:
£ 6,564.70
Step-by-step explanation:
Henry places £6000 in an account which pays 4.6% compound interest each year. Calculate the amount in his amount after 2 years
Compound Interest formula =
A = P(1 + r/n)^nt
A = Final Amounrt
P = Principal = £6,000
r = Interest rate = 4.6%
t = Time in years = 2 years
n = Compounding frequency = Yearly = 1
First, convert R percent to r a decimal
r = R/100
r = 4.6%/100
r = 0.046 per year,
Then, solve our equation for A
A = P(1 + r/n)^nt
A = 6,000.00(1 + 0.046/1)^(1×2)
A = £ 6,564.70
The amount in his account after 2 years = £ 6,564.70
Answer:
True expressions:
- The constants, -3 and -8, are like terms.
- The terms 3 p and p are like terms.
- The terms in the expression are p squared, negative 3, 3 p, negative 8, p, p cubed.
- The expression contains six terms.
- Like terms have the same variables raised to the same powers.
Step-by-step explanation:
The expression is:
p² - 3 + 3p - 8 + p + p³
False expressions:
- The terms p squared, 3 p, p, and p cubed have variables, so they are like terms. (They don't have the same exponents)
- The terms p squared and p cubed are like terms. (They don't have the same exponents)
- The expression contains seven terms. (It contains 6 terms)
Answer:
f(-1) = 0
f(2) = 16
Step-by-step explanation:
f(-1) = 4(-1) + 4 = 0
f(2) = 4(2) + 8 = 16
Answer:
1.7
Step-by-step explanation:
1/2 (2 x anything) = anything
1/2 cancels out the 2