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masha68 [24]
3 years ago
11

Find the value of x. PLEASE HELP

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

Answer:

14*

Step-by-step explanation:

5x+4*=74*

-4          -4

5x=70*

x=14*

*dont mind the asterisks they are my temporary degree signs

hope this helps

brainliest?

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Step-by-step explanation:

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Can anybody help me out with this problem pleaseee :D
Oksanka [162]
<h3>Answer: 10</h3>

Explanation:

"percent" means "per one hundred". Think "cent" as in "100 cents in a dollar". That's one way to remember.

So when we say something like 2%, we mean 2 out of 100 leading to the fraction 2/100 = 0.02

The same applies for 4.8% turning into 4.8/100 = 0.048

A quick shortcut without the use of a calculator has us move the decimal point 2 spots to the left to go from 4.8% to 0.048

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After converting 4.8% to 0.048, we then multiply this by 200

200*(0.048) = 9.6

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2y-4x=-12 what is the slope intercept
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According to the Knot, 22% of couples meet online. Assume the sampling distribution of p follows a normal distribution and answe
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Using the <em>normal distribution and the central limit theorem</em>, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 22% of couples meet online, hence p = 0.22.
  • A sample of 150 couples is taken, hence n = 150.

Item a:

The mean and the standard error are given by:

\mu = p = 0.22

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 0.25</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{0.25 - 0.22}{0.0338}

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the <u>p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15</u>, hence:

X = 0.2:

Z = \frac{X - \mu}{s}

Z = \frac{0.2 - 0.22}{0.0338}

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

Z = \frac{X - \mu}{s}

Z = \frac{0.15 - 0.22}{0.0338}

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

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Step-by-step explanation:

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