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blsea [12.9K]
2 years ago
14

HALP URGENT PLS im dum x =x=x, equals ^\circ ∘

Mathematics
2 answers:
belka [17]2 years ago
8 0

Answer:

x = 55°

Step-by-step explanation:

That square box indicates a right angle.

A right angle is 90°.

We know that angle x and the 35° angle are making up this 90° angle together.

So, the equation to show what this ship looks like is the following:

x+35=90

This is a simple equation, that if we solve, we get:

x=55

So, x is 55°.

deff fn [24]2 years ago
7 0

Considering the angle of the ray, it is found that the value of x is of x = 55º.

<h3>What is the angle of the ray?</h3>

The ray has an angle of 180º. It is composed by:

  • Angle x.
  • An angle of 35º.
  • An angle of 90º.

Hence:

x + 35 + 90 = 180

x = 180 - 125

x = 55º.

More can be learned about angles and rays at brainly.com/question/25770607

#SPJ1

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A box with a square base and open top must have a volume of 296352 c m 3 . We wish to find the dimensions of the box that minimi
mestny [16]

Answer:

  • Base Length of 84cm
  • Height of 42 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume, V=x^2h=296352

h=\dfrac{296352}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

A(x,h)=x^2+4xh\\$Substitute h=\dfrac{296352}{x^2}\\A(x)=x^2+4x\left(\dfrac{296352}{x^2}\right)\\A(x)=\dfrac{x^3+1185408}{x}

Step 2: Find the derivative of A(x)

If\:A(x)=\dfrac{x^3+1185408}{x}\\A'(x)=\dfrac{2x^3-1185408}{x^2}

Step 3: Set A'(x)=0 and solve for x

A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84

Step 4: Verify that x=84 is a minimum value

We use the second derivative test

A''(x)=\dfrac{2x^3+2370816}{x^3}\\$When x=84$\\A''(x)=6

Since the second derivative is positive at x=84, then it is a minimum point.

Recall:

h=\dfrac{296352}{x^2}=\dfrac{296352}{84^2}=42

Therefore, the dimensions that minimizes the box surface area are:

  • Base Length of 84cm
  • Height of 42 cm.
5 0
3 years ago
F.O.
german
You need to review the question and ask again. Not enough info.
4 0
3 years ago
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