Answer:
See below
Step-by-step explanation:
We start by dividing the interval [0,4] into n sub-intervals of length 4/n
![[0,\displaystyle\frac{4}{n}],[\displaystyle\frac{4}{n},\displaystyle\frac{2*4}{n}],[\displaystyle\frac{2*4}{n},\displaystyle\frac{3*4}{n}],...,[\displaystyle\frac{(n-1)*4}{n},4]](https://tex.z-dn.net/?f=%5B0%2C%5Cdisplaystyle%5Cfrac%7B4%7D%7Bn%7D%5D%2C%5B%5Cdisplaystyle%5Cfrac%7B4%7D%7Bn%7D%2C%5Cdisplaystyle%5Cfrac%7B2%2A4%7D%7Bn%7D%5D%2C%5B%5Cdisplaystyle%5Cfrac%7B2%2A4%7D%7Bn%7D%2C%5Cdisplaystyle%5Cfrac%7B3%2A4%7D%7Bn%7D%5D%2C...%2C%5B%5Cdisplaystyle%5Cfrac%7B%28n-1%29%2A4%7D%7Bn%7D%2C4%5D)
Since f is increasing in the interval [0,4], the upper sum is obtained by evaluating f at the right end of each sub-interval multiplied by 4/n.
Geometrically, these are the areas of the rectangles whose height is f evaluated at the right end of the interval and base 4/n (see picture)

but

so the upper sum equals

When
both
and
tend to zero and the upper sum tends to

Look at the graph of the equation.
The minimum is (5,-9).
The answer could be a=5.6
The answer would be -10p64q^1
since -10^3(p^4)^3 (q^1)^3 is -1000p^12q^3
m(w) = 8w + 17 looks like the best answer choice for me