Question

(1.) When aqueous solutions of Fe(NO3)3 and NaOH are mixed, Fe(OH)3 and NaNO3 are formed. is there a precipitate formed? if yes, write the formula for the precipitate and explain why it is the precipitate using the solubility rules. (2.) When aqueous solutions of potassium iodide and Lead (II) nitrate are combined, potassium nitrate and solid lead (II) iodide are formed. Write the balanced,complete ionic and net ionic equations for this reaction

Answer 1

From the solubility rules, both reactions 1 and 2 lead to precipitates.

What is a precipitate?

The term precipitate refers to the solid that separates out of the reaction mixture . We know that the solubility of a substance in water is predicated on the solubility rules.

1) The reaction here is;

Fe(NO3)3(aq) +  3NaOH(aq) ------> Fe(OH)3(s) + 3NaNO3(aq) - The precipitate is  Fe(OH)3 because only the hydroxides of group 1 elements are soluble in water.

2) The reaction is;

Pb(NO3)2(aq) + 2KI(aq) ----->PbI2(s) + 2NaNO3(aq) - The precipitate is PbI2 because most iodides are soluble except the iodides of  Ag+, Hg+2, and Pb+2

Complete Ionic equation;

Pb^2+(aq) + 2NO3^-(aq) + 2K^+(aq) + 2I^-(aq) ------> PbI2(s) +  2NO3^-(aq) + 2K^+(aq)

Net ionic equation;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Learn more about the solubility rules:brainly.com/question/12978582

##SPJ1