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Eva8 [605]
3 years ago
9

NEED HELP ASAP PLEASE

Physics
1 answer:
Zarrin [17]3 years ago
8 0

Answer:

D. 3.0 m/s

Explanation:

because I did this in my class

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A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 59 ms. (a
xxTIMURxx [149]

Answer:y_{com}=0.707 m

v_{com}=3.713 m/s

Explanation:

Given

first stone mass is m

second stone mass is 6 m

distance traveled by  first stone in 430 ms

y_1=ut+\frac{at^2}{2}

y_1=0+\frac{g(0.43)^2}{2}

y_1=0.9069 m

Distance traveled by stone 2 in t=430-59=371 ms

y_2=ut+\frac{at^2}{2}

y_2=0+\frac{g(0.0.371)^2}{2}

y_2=0.674 m

velocity of first stone after t=0.43 s

v_1=u+at

v_1=0+9.8\times 0.43=4.214 m/s

velocity of second stone after t=0.371 s

v_2=u+at

v_2=0+9.8\times 0.371=3.63 m/s

Position of Center of mass of system

y=\frac{y_1m_1+y_2m_2}{m_1+m_2}

y=\frac{0.9069\times m+0.674\times 6m}{m+6m}

y=\frac{4.95m}{7m}=0.707 m

Velocity of COM

v_{com}=\frac{v_1m_1+v_2m_2}{m_1+m_2}

v_{com}=\frac{4.214\times m+3.63\times 6m}{m+6m}

v_{com}=3.713 m/s

6 0
4 years ago
By what primary method of heat transfer does the sun warm the earth?
GenaCL600 [577]
Sun warms the earth with Electromagnetic Radiations.

Sun emits out short range radiation in the form of Electromagnetic (EM) Radiation. Our Atmosphere is transparent to EM radiation. It does not heats up the atmosphere but when it collide with the solid objects or particles it is absorbed, reflected or refracted and the object heats up and start emitting radiation in the form of long wave radiation. Our Earth does the same. The long wave radiation emitted by the earth surface is absorbed by our atmosphere and it heats up. Therefore, we can say our atmosphere is heated from below.
5 0
3 years ago
A ball rolls of a cliff and when it lands has a vertical velocity 35 ms ^-1. how high was the cliff?
Licemer1 [7]
Using V²=u² +2gH
let's assume the ball falls from rest, then it's initial velocity = 0ms-¹ (U=0)
then from the above info V= 35ms-¹
g= 10ms-² (value of acceleration due to gravity to the nearest tens)

so input your values above into the given formula to find height
35² = 0² +2×10×H
1225 = 20H
H = 1225÷20 = 61.25m
6 0
4 years ago
Where would the barycenter of these two bodies be located given their masses?
n200080 [17]

It's kinda tough, since we don't know the actual numerical locations of the points, only an approximate picture.

The big ball has 11 times the mass of the small ball, so the small ball is 11 times as far from the barycenter as the big ball is.

If any of the points is marked at the actual barycenter, it can only be point-A .

3 0
3 years ago
There is evidence that elephants communicate via infrasound, generating rumbling vocalizations as low as 14 Hz that can travel u
amid [387]

Answer:

L = 96.2 dB

Explanation:

As we know that the level of intensity is given as

\beta = 10Log(\frac{I}{I_o})

here we know

\beta = 104 dB

104 = 10Log(\frac{I}{10^{-12}})

I = 0.025 W/m^2

now the sound is travelling in all possible directions so we have

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

\frac{0.025}{I_2} = \frac{10^2}{4.1^2}

I_2 = 4.2 \times 10^{-3} W/m^2

now for level of sound we have

L = 10Log(\frac{4.2 \times 10^{-3}}{10^{-12}})

L = 96.2 dB

5 0
3 years ago
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