The perimeter of a rectangle the painting is 272 cm the length of the painting is 78 cm what is the width

Mathematics

1 answer:

tatyana61 [14]2 years ago

4 0

Answer:

Step-by-step explanation:

Basically, your equation will look like this

2W=272-(78+78)

2W=272-156

2W=116

but now you have to divide by 2

W=58

You might be interested in

What is the value of g(9)?

ryzh [129]

I think B should be the answer

6 0

3 years ago

Fractions order from least to greatest<br> Which is the right answer? Pls help ill give brainliest!!

olya-2409 [2.1K]

Answer:

2/5, 4/7, 5/2

Step-by-step explanation:

5/2=2.5 2/5=.40 4/7= .59 that's aproximately for 4/7

8 0

3 years ago

I need help with my homework

Vesna [10]

2x tablespoons i believe

7 0

3 years ago

Find y'' by implicit differentiation. 4x^3 + 5y^3 = 4

iVinArrow [24]

$\bf 4x^3+5y^3=4\implies 12x^2+15y^2\cfrac{dy}{dx}=0\implies 4x^2+5y^2\cfrac{dy}{dx}=0
\\\\\\
5y^2\cfrac{dy}{dx}=-4x^2\implies \boxed{\cfrac{dy}{dx}=\cfrac{-4x^2}{5y^2}}\\\\
-------------------------------\\\\
\cfrac{d^2y}{dx^2}=\stackrel{quotient~rule}{\cfrac{-8x(5y^2)~~-~~(-4x^2)(10y)\left( \frac{dy}{dx} \right)}{(5y^2)^2}}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}$

$\bf \cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2-\frac{160x^4y}{5y^2}}{25y^4}\implies 
\cfrac{d^2y}{dx^2}=\cfrac{\frac{-200xy^4-160x^4y}{5y^2}}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-200xy^4-160x^4y}{(25y^4)(5y^2)}\implies 
\cfrac{d^2y}{dx^2}=\cfrac{-200xy^4-160x^4y}{125y^6}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^4-32x^4y}{25y^6}$

6 0

3 years ago

What is the decimal value of tan X?

Serggg [28]

we will look at the angle corresponding to X

adjacent =13

opposite =84

we can use formula

$tan(X)=\frac{opposite}{adjacent}$