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2 years ago

The perimeter of a rectangle the painting is 272 cm the length of the painting is 78 cm what is the width

Mathematics

1 answer:

tatyana61 [14]2 years ago

4 0

Answer:

Step-by-step explanation:

Basically, your equation will look like this

2W=272-(78+78)

2W=272-156

2W=116

but now you have to divide by 2

W=58

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storchak [24]

Answer:

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Step-by-step explanation:

4-xy=y^3

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Solving for dy/dx: Addind x dy/dx both sides of the equation:

$-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}$

Common factor dy/dx on the right side of the equation:

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Dividing both sides of the equation by 3y^2+x:

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3 years ago

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Step-by-step explanation:

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2 years ago

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3 years ago

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alexandr402 [8]

Answer:

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Step-by-step explanation:

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3 years ago

The perimeter of a rectangle the painting is 272 cm the length of the painting is 78 cm what is the width￼

The perimeter of a rectangle the painting is 272 cm the length of the painting is 78 cm what is the width