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Volgvan
2 years ago
5

Calcium (Ca) and diatomic oxygen (O2) combine to form calcium oxide (CaO). The data table below compares the properties of these

substances.
Calcium (Ca) Oxygen (O2) Calcium Oxide (CaO)
Melting Point (°C) 842 −218.4 2613
Density (g/cm3) 1.54 0.00143 3.34
Appearance silvery-white
metal colorless,
odorless gas white, odorless
powder

What can be concluded from this data?
A.
A chemical reaction occurred because calcium oxide has different properties than calcium and diatomic oxygen.
B.
A chemical reaction did not occur because solid calcium cannot chemically react with diatomic oxygen gas.
C.
A chemical reaction did occur because calcium oxide has similar properties to calcium and diatomic oxygen.
D.
A chemical reaction did not occur because calcium oxide is not a new substance.
Chemistry
1 answer:
Elenna [48]2 years ago
3 0

A chemical reaction occurred because calcium oxide has different properties than calcium and diatomic oxygen. The correct option is A.

<h3>What are chemical reactions?</h3>

A chemical reaction is said to occur when the chemical properties of substances change during the course of the reaction.

From the illustration, the chemical properties of calcium oxide are unique from that of calcium and oxygen. Thus, calcium oxide has become a new substance entirely.

Once a reaction leads to the formation of new substances, such a reaction is a chemical reaction.

More on chemical reactions can be found here: brainly.com/question/22817140

#SPJ1

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A first order reaction has rate constants of 4.6 x 10-2 s-1 and 8.1 x 10-2 s-1 at 0ºC and 20ºC, respectively. What is the value
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At 0°C, which is 0 + 273 = 273 Kelvins, the rate constant k is 4.6*10^{-2}. So:

k=Ae^{\frac{-E_a}{RT}

4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}

At 20°C, which is 20 + 273 = 293 Kelvins, the rate constant k is 8.1*10^{-2}. So:

k=Ae^{\frac{-E_a}{RT}

8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}

We now have two equations and two variables to solve for. We just want to find Ea, so let's write the first equation for A in terms of Ea:

4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}

A=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }

Plug this in for A in the second equation:

8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}

8.1*10^{-2}=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }e^{\frac{-E_a}{8.31*293}

After some troublesome manipulation, the answer should come down to be approximately:

Ea = 18,800 J/mol

The answer is thus D.

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