Answer:
NO is the limiting reactant.
0.893 moles of NO2 will be produced
Explanation:
Step 1: Data given
Number of moles NO = 0.893 moles
Number of moles O2 = 0.519 moles
Step 2: The balanced equation
2NO + O2 → 2NO2
Step 3: Calculate the limiting reactant
For 2 moles NO we need 1 mol O2 to produce 2 moles NO2
NO is the limiting reactant. It will completely be consumed. (0.893 moles)
O2 is in excess. There will react 0.893/2 = 0.4465 moles.
There will remain 0.519 - 0.4465 = 0.0725 moles O2
Step 4: Calculate moles NO2
For 2 moles NO we need 1 mol O2 to produce 2 moles NO2
For 0.893 moles NO we'll have 0.893 moles NO2
NO is the limiting reactant.
0.893 moles of NO2 will be produced
