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gavmur [86]
3 years ago
12

5. On a business trip Bob traveled 245.22 miles. If gasoline was $2.87 per gallon and the car averaged 25.3 miles per gallon, de

termine the cost of the trip. (Round to the nearest cent)
Mathematics
1 answer:
Alecsey [184]3 years ago
4 0

The total cost of the trip was $27.81

Step-by-step explanation:

Given,

Distance traveled = 245.22 miles

Distance traveled per gallon = 25.3 miles

Gallons used for 245.22 miles = \frac{Total\ distance}{Distance\ per\ gallon}

Gallons used for 245.22 miles = \frac{245.22}{25.3} = 9.69\ gallons

9.69 gallons were used for 245.22 miles.

Cost per gallon = $2.87

Cost of 9.69 gallons = 2.87*9.69 = $27.81

The total cost of the trip was $27.81

Keywords: division, multiplication

Learn more about division at:

  • brainly.com/question/2115122
  • brainly.com/question/2116906

#LearnwithBrainly

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Suppose f(x) = x^2 and
SpyIntel [72]

Given:

The two functions are:

f(x)=x^2

g(x)=\left(\dfrac{1}{3}x\right)^2

To find:

The statement that best compares the graph of g(x) with the graph of f(x).

Solution:

The horizontal stretch is defined as:

g(x)=f(kx)            ...(i)

If 0, the function f(x) is horizontally stretched by factor \dfrac{1}{k}.

If k>1, the function f(x) is horizontally compressed by factor \dfrac{1}{k}.

We have,

f(x)=x^2

g(x)=\left(\dfrac{1}{3}x\right)^2

Using these functions, we get

g(x)=f\left(\dfrac{1}{3}x\right)         ...(ii)

On comparing (i) and (ii), we get

k=\dfrac{1}{3}

Since 0, the function f(x) is horizontally stretched by factor \dfrac{1}{\frac{1}{3}}=3.

Hence, the correct option is D.

5 0
3 years ago
When 12 is added to a number the result is 32 less than 3 times the number.
sdas [7]


Let the number = x

12 + x = 3x - 32

x = 3x - 44 Subtract 12 from both sides

-2x = -44 Subtract 3x from both sides

x = 22 Divide by -2

4 0
3 years ago
Read 2 more answers
Matt he bought five book he needed 9 how many more he needed
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Answer:

5

Step-by-step explanation:

4 0
3 years ago
You borrow $5,000 from your parents to purchase a used car. The arrangements of the loan are such that you make payments of $250
AfilCa [17]
Part A:
1st month: Interest payable = 1% of $5,000 = $50.00
Amount paid in first month = $250 + $50.00 = $300
Unpaid balance = $5,000 - $250 = $4,750

2nd month: Interest payable = 1% of $4,750 = $47.50
Amount paid in second month = $250 + $47.50 = $297.50
Unpaid balance = $4,750 - $250 = $4,500

3rd month: Interest payable = 1% of $4,500 = $45.00
Amount paid in third month = $250 + $45.00 = $295.00
Unpaid balance = $4,500 - $250 = $4,250

4th month: Interest payable = 1% of $4,250 = $42.50
Amount paid in fouth month = $250 + $42.50 = $292.50
Unpaid balance = $4,250 - $250 = $4,000

5th month: Interest payable = 1% of $4,000 = $40.00
Amount paid in fifth month = $250 + $40.00 = $290.00
Unpaid balance = $4,000 - $250 = $3,750

6th month: Interest payable = 1% of $3,750 = $37.50
Amount paid in sixth month = $250 + $37.50 = $287.50
Unpaid balance = $3,750 - $250 = $3,500

7th month: Interest payable = 1% of $3,500 = $35.00
Amount paid in seventh month = $250 + $35.00 = $285.00
Unpaid balance = $3,500 - $250 = $3,250

8th month: Interest payable = 1% of $3,250 = $32.50
Amount paid in eighth month = $250 + $32.50 = $282.50
Unpaid balance = $3,250 - $250 = $3,000

9th month: Interest payable = 1% of $3,000 = $30.00
Amount paid in ninth month = $250 + $30.00 = $280.00
Unpaid balance = $3,000 - $250 = $2,750

10th month: Interest payable = 1% of $2,750 = $27.50
Amount paid in fouth month = $250 + $27.50 = $277.50
Unpaid balance = $2,750 - $250 = $2,500

11th month: Interest payable = 1% of $2,500 = $25.00
Amount paid in seventh month = $250 + $25.00 = $275.00
Unpaid balance = $2,500 - $250 = $2,250

12th month: Interest payable = 1% of $2,250 = $22.50
Amount paid in eighth month = $250 + $22.50 = $272.50
Unpaid balance = $2,250 - $250 = $2,000



Part B:
Number of payments = 5000 / 250 = 20
Total amount of interest = 50 + 47.5 + 45 + . . . + upto the 20th payment.
This is an arithmetic sequence with the first term as 50, common difference as -2.5 and number of terms = 20.

Sum of the first 20th term of the GP is given by
S_n= \frac{20}{2}[2(50)+(20-1)(-2.5)] \\  \\ =10(100-2.5(19))=10(100-47.5) \\  \\ =10(52.5)=\$525.00

Therefore, the <span>total amount of interest paid over the term of the loan is $525.00</span>
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3 years ago
A rectangular pool in your friends yard 150 ft. x 400 ft. Create a scale drawing with a scale factor of 1/600 use a table or an
timurjin [86]

Answer:

150 ft. x 400 ft. = 60,000

Step-by-step explanation:

3 0
3 years ago
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