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Dahasolnce [82]
2 years ago
5

F(x)=x^2-x-56=0 what are the zeros in the function? please help!!!

Mathematics
1 answer:
Maksim231197 [3]2 years ago
4 0

Answer:

-7, 8.

Step-by-step explanation:

x^2 - x - 56 = 0

Let's see if we can factor this function:

We need 2 numbers whose product is -56 and whose sum is -1 ( which is the coefficient of x).

They are  -8 and 7 , so the factors are:

(x - 8)(x + 7) = 0

x - 8 = 0 giving x =  8 and

x + 7 = 0 giving x = -7.

The zeros are -7, 8

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Step-by-step explanation:

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Hi there...

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Aneli [31]

Answer:

Could you please show me a graph so I can answer more clearly? I'll follow up on this question if it helps.

Step-by-step explanation:

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lutik1710 [3]
First, I'd simplify this problem by dividing every term by 2:

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Let's try x = -4 as a possible root.  Setting up and using synthetic division:

      ____________________
-4  /   1   -4   5    -4    4
              -4   32
     ----------------------------
         1    -8  37

This result is not helpful.  So, try the possible root +4 instead:
       ________________
+4  /   1   -4   5    -4    4
                4    0   20   64
       ----------------------------
         1     0    5    16   68             4 is not a root because the remainder   
                                                    (68) is not zero.

Try x = 2:

       ________________
+2  /   1   -4   5    -4    4
                2   -4    2    -40
       ----------------------------
          1    -2   1    -2    0

2 is a root because the remainder is zero.

Continue this process until you've found the other 3 roots.

Hint:  Try  the possible root x = -2 with the following coefficients:

     ____________
-2 /  1   -2   1   -2

    ---------------------
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