3 years ago

Please help me i don’t know how to solve this

Mathematics

1 answer:

murzikaleks [220]3 years ago

3 0

Answer:

welp good luck ha

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

3x-12=12x

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$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

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Step-by-step explanation:

For this case we have the following equation given:

$x^2 +4x +y^2 -20 y +100=0$

We want to find a general expression given by:

$(x-h)^2 +(y-k)^2 = r^2$

Where the center is (h.k) and the radius is r.

We can begin completing the squares of the equation given and we got:

$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

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$x^2 +4x+ 4 +y^2 +20y +100 +100 = 4 +100$

If we subtract 100 from both sides we got:

$(x+2)^2 +(y+10)^2 = 4$

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