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Setler79 [48]
3 years ago
6

The steepest angle at which a pile of unconsolidated grains remains stable is called the

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0
It is the angle of repose
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Z to the power of 2 =1
stiv31 [10]

That would be written as:

z^{2} = 1


And the step-by-step equation would be:

z^{2} = 1 → we take the 2 to the right side of the equation and do the IO*

z = \sqrt{1} →we solve for \sqrt{1}

z = 1 → final answer


*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)



Hope it helped,



BioTeacher101

3 0
3 years ago
An equation for the depreciation of a car is given by y = A(1 – r)t , where y = current value of the car, A = original cost, r =
Mamont248 [21]
<h2>The car is about 6.6 years old.</h2>

Step-by-step explanation:

Given : An equation for the depreciation of a car is given by y = A(1-r)^t, where y = current value of the car, A = original cost, r = rate of depreciation, and t = time, in years. The value of a car is half what it originally cost. The rate of depreciation is 10%.

To find : Approximately how old is the car?

Solution :

The value of a car is half what it originally cost i.e. y=\frac{1}{2} A

The rate of depreciation is 10% i.e. r=10%=0.1

Substitute in the equation, y = A(1-r)^t

\frac{1}{2} A= A(1-0.1)^t

\frac{1}{2}= (0.9)^t

Taking log both side,

\log(\frac{1}{2})=t\log (0.9)

t=\frac{\log(\frac{1}{2})}{\log (0.9)}

t=6.57

t\approx 6.6

Therefore, the car is about 6.6 years old.

3 0
3 years ago
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How do you round 103.468 to the nearest liter?
sergeinik [125]
103 stays because it is the whole number and the next number after the decimal is below 5.

103 is your answer.
8 0
3 years ago
Hello please help i’ll give brainliest
olga_2 [115]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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A line passes through the point (4,-1) and (2,3)
Sholpan [36]

Answer:

Ok.... whats the Rest of the question Type it in the comments and i will edit this answer

Step-by-step explanation:

7 0
3 years ago
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