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USPshnik [31]
3 years ago
10

Represent the interval where both functions are increasing on the number line provided.

Mathematics
1 answer:
Luda [366]3 years ago
3 0

Answer:

The interval of increasing for both the given functions f((x) and g(x) is given by : (-∞, 4)

Step-by-step explanation:

The function f(x) = |3x| + 3

Since, The modulus function is always increasing so adding 3 to it also increase over the whole number line.

So, The interval of increasing for the function f(x) : (-∞, +∞)

The function g(x) = -x² + 8x - 5

⇒ g'(x) = -2x + 8

To find critical points : g'(x) = 0

⇒ -2x + 8 = 0

⇒ x = 4

So, Intervals of increasing or decreasing are : (-∞, 4) and (4, +∞)

Now, On checking g(x) is increasing on (-∞, 4) and decreasing on (4, +∞)

Hence, The interval of increasing for both the given functions f((x) and g(x) is given by : (-∞, 4)

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Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

So the joint density function is given as

f(x,y)=\left \{ {{\dfrac{x}{8}e^{-\dfrac{x+y}{2}}    \,\,\,\,0 \leq x,0\leq y \atop {0}} \right.

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f_x=\int\limits^{\infty}_0 {f(x,y)} \, dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x+y}{2} }dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x}{2}}e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{8}e^{-\frac{x}{2}}\int\limits^{\infty}_0e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{4}e^{-\frac{x}{2}}

Now

f(Y/X)=\dfrac{f(X,Y)}{f(X)}\\f(Y/X)=\dfrac{\dfrac{x}{8}e^{-\frac{x+y}{2} }}{\dfrac{x}{4}e^{-\frac{x}{2}}}\\f(Y/X)=\dfrac{1}{2}e^{-\frac{y}{2} }

Now the value of E(Y/X) is given as

E(Y/X)=\int\limits^{\infty}_0 {yf_{Y/X}} \, dy \\E(Y/X)=\int\limits^{\infty}_0 {y\dfrac{1}{2}e^{-\frac{y}{2} } }\, dy\\E(Y/X)=\dfrac{1}{2}\dfrac{\sqrt{2}}{(\dfrac{1}{2})^2}=2

So the value of E(Y/X) is 2.

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