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Oksanka [162]
3 years ago
8

Sneakychicken help me ​

Mathematics
1 answer:
12345 [234]3 years ago
5 0

Answer:

x, process, y

-2, -2-1, -3

-1, -1-1, -2

0, 0-1, -1

1, 1-1, 0

2, 2-1, 1

X = -2, -1, 0, 1, 2

Y = -3, -2, -1, 0, 1

Step-by-step explanation:

Coordinates for the graph are ( -2,-3), (-1,-2), (0,-1), (1,0), (2,1)

The graph is the image attached to this.

How to get Y:

-2-1= -3

-1-1= -2

0-1= -1

1-1= 0

2-1= 1

Hope this helps.

You might be interested in
If k(x) = 5x-6, which expression is equivalent to (k+k) (4)?
goldenfox [79]

Answer:

<em>5(4) - 6 + 5(4) - 6</em>

Step-by-step explanation:

k(x) = 5x - 6

(k+k)(x) = 5x - 6 + 5x - 6

(k+k)(4) = 5(4) - 6 + 5(4) - 6

=> Option D is correct

Hope this helps!

5 0
3 years ago
Customers arrive at a restaurant according to a Poisson distribution at a rate of 20 customers per hour. The restaurant opens fo
jenyasd209 [6]

Answer:

0.087

Step-by-step explanation:

Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:

= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:

X₅ ~ Poisson (20 (5/60))

X₅ ~ Poisson (1.6667)

Formula for computing probabilities for Poisson is as follows:

P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!

P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! =  (e^-1.6667)((1.6667²)/3!)

P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)

P(X₅= 3) = (2.718^(-1.6667))0.46

P(X₅= 3) = 0.1889×0.46

P(X₅= 3) = 0.086894

P(X₅= 3) = 0.087

Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.

8 0
3 years ago
On a certain airline, customers are assigned a row number when they purchase their ticket, but the four seats within the row are
maksim [4K]

Answer:

The probability that they sit next to each other is 50%.

Step-by-step explanation:

Consider the provided information.

It is given that there are four seats within the row are first come, first served during boarding.

There are 4 seats and 2 customers (Karen and Georgia)

The total number of ways in which Karen and Georgia can sit is: ^4C_2

Now if they will sit together, then consider  Karen and Georgia as a single unit.

Thus, the number of ways in which they can sit together is: ^3C_1

The required probability is:

P=\frac{^3C_1}{^4C_2} \\\\P=\frac{3}{6}\\\\P=\frac{1}{2}

Hence, the probability that they sit next to each other is 50%.

6 0
2 years ago
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
Please help me with this!
Airida [17]

Step-by-step explanation:

→ 42 = 7u - u

→ 42 = 6u

→ 42/6 = u

→ 7 =u or U = 7

<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> dear</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care </u></em><em><u>and</u></em><em><u> may</u></em><em><u> u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em>

4 0
3 years ago
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