All categories

2 years ago

Sneakychicken help me

Mathematics

1 answer:

12345 [234]2 years ago

5 0

Answer:

x, process, y

-2, -2-1, -3

-1, -1-1, -2

0, 0-1, -1

1, 1-1, 0

2, 2-1, 1

X = -2, -1, 0, 1, 2

Y = -3, -2, -1, 0, 1

Step-by-step explanation:

Coordinates for the graph are ( -2,-3), (-1,-2), (0,-1), (1,0), (2,1)

The graph is the image attached to this.

How to get Y:

-2-1= -3

-1-1= -2

0-1= -1

1-1= 0

2-1= 1

Hope this helps.

You might be interested in

Which polynomial is equivalent to 4n + 5^2

tankabanditka [31]

Answer:

16n^2+40n+25

Step-by-step explanation:

4 0

2 years ago

The sum of two numbers is 41 . The smaller number is 11 less than the larger number . What are the numbers ?

AleksAgata [21]

26 and 15 is the answer!

4 0

3 years ago

What is 0.8525641 rounded 2 decimal places!

lilavasa [31]

Answer:

0.85

Step-by-step explanation:

3 0

2 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers

Use the equation and type the ordered-pairs.

matrenka [14]

Hello!

To find the y-values of the given ordered pairs, substitute the x-values into the equation, y = log₂ x.

y = log₂ 1/2, y = -1

y = log₂ 1, y = 0

y = log₂ 2, y = 1

y = log₂ 4, y = 2

y = log₂ 8, y = 3

y = log₂ 16, y = 4

Therefore, the ordered pairs of y = log₂ x is: {(1/2, -1), (1, 0), (2, 1), (4, 2), (8, 3), (16, 4)}.

5 0

3 years ago

Read 2 more answers

Sneakychicken help me ​

Sneakychicken help me