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Tju [1.3M]
2 years ago
12

Cooling towers are used to remove or expel heat from a process. A cooling tower's walls are modeled by where the measurements ar

e in meters. What is the width of the cooling tower at the base of the structure
Mathematics
1 answer:
djverab [1.8K]2 years ago
7 0

The width of the cooling tower is 36 meters.

<h3>What is a cooling tower?</h3>

A cooling tower is a vent that is built for the purpose of releasing waste heat back to the atmosphere.

Now we can model the system using;  x²/324 - (y² - 90)²/1600. Thus, the width can be obtained from;

2 × ✓324

= 2 × 18

= 36 meters

Learn more about cooling tower:brainly.com/question/26654522

#SPJ1

Missing parts;

Cooling towers are used to remove or expel heat from a process. A cooling tower's walls are modeled by x squared over 324 minus quantity y minus 90 end quantity squared over 1600 equals 1 comma where the measurements are in meters. What is the width of the cooling tower at the base of the structure? Round your answer to the nearest whole number.

36 meters

48 meters

80 meters

89 meters

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Answer:

T4 = -2°F

Step-by-step explanation:

Given the following data;

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Time, t = 4 hours

In four (4) hours, we have;

T = kt

Substituting into the equation, we have;

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T4 = current temp - new temp

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Therefore, the temperature it will be in 4 hours is - 2°F.

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x + y = 10

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I need the solution
Nataly [62]

The only thing you can do here is to try to simplify, so I'll assume that's what you want to do.

\dfrac{b^2-a^2}{2a^2+ab-3b^2}

The numerator is a difference of squares, so it's easy to factorize:

b^2-a^2=(b-a)(b+a)

In the denominator, we factorize by grouping:

2a^2+ab-3b^2=2a^2-2ab+3ab-3b^2=2a(a-b)+3b(a-b)=(2a+3b)(a-b)

So we have

\dfrac{b^2-a^2}{2a^2+ab-3b^2}=\dfrac{(b-a)(b+a)}{(2a+3b)(a-b)}=-\dfrac{b+a}{2a+3b}

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Can somebody help me? With those three problems please
s2008m [1.1K]

Answer:

15. x = 8

16. m<V = 103°

17. x = 14

Step-by-step explanation:

15. The figure given is quadrilateral. Sum of interior angles of a quadrilateral = 360°

Therefore:

(10x + 6) + (13x - 2) + (8x - 1) + (180 - 71) = 360

Solve for x

10x + 6 + 13x - 2 + 8x - 1 + 109 = 360

Add like terms

31x + 112 = 360

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31x = 248

Divide both sides by 31

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16. The polygon is a hexagon. Sum of interior angles of a hexagon = 720. Therefore:

90 + (7x + 3) + 128 + (5x + 8) + 111 + (9x - 19) = 720

Solve for x

90 + 7x + 3 + 128 + 5x + 8 + 111 + 9x - 19 = 720

Add like terms

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Subtract 321 from each side

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Therefore:

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Solve for x

9x - 18 = 108

Add 18 to both sides

9x = 126

Divide both sides by 9

x = 14

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3 years ago
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