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2 years ago

Need help wasn't there for a lesson

Mathematics

1 answer:

77julia77 [94]2 years ago

6 0

These are linear equations, so there is x and y. On number one the first thing they plotted was (3,8) so in a function table the 3 would be on the left side and the 8 would be on the right side. I’ll leave you with the rule of the first one, if the rule is times 2 plus to the how would you put it in a function table.

The first thing that you would put into the function table on the first question would be as I said earlier 3 and then 8. The rule is the rate. Using a function table will be very helpful (That’s why I keep mentioning one). Let me know if this helps.

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Variance = 0.58

Step-by-step explanation:

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To find:

mean and variance of X

Solution:

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Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

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----$$$$$$$

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slavikrds [6]

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