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Arte-miy333 [17]
2 years ago
5

Help me please I’m not the smartest

Mathematics
1 answer:
viktelen [127]2 years ago
3 0
X^2=16
x= 4 OR x=-4

The picture attached below is your answer because it’s between 4 and -4.

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The volume of an object is given as a function of time by V = A + B t + C t4 . Find the dimension of the constant C
aksik [14]

Answer:

The dimensions of constant C are of [L^{3}T]^{-4}

Step-by-step explanation:

It is given that

V(t)=A+Bt+Ct^{3}

Since the dimensions of volume are [L^{3}]

Each of the term shall have a dimension of [L^{3}] since they are in addition.

Thus for third term we can write

Thus we have

[L^{3}]=[C][T^{4}]\\\\\therefore [C]=[L^{3}][T^{-4}]

5 0
3 years ago
At the local department store sweaters have been reduced to $15 this price is at 75% of the original price for sweaters given th
BartSMP [9]
Since 75% = 3/4
then $15 = 3/4 of the original price

Divide 15 ÷ 3 to get the 25% of the original price
(1/4 of the price)

15 ÷ 3 = 5

$5 is the 25% of the original price

so, if 25% + 75% = 100%
then $5 + $15 = $20

The original price for the sweaters was $20.

Any Questions? Please leave a comment ! (:
3 0
3 years ago
What substitution should be used to rewrite 6(x + 5)2 + 5(x + 5) – 4 = 0 as a quadratic equation? u = (x + 5) u = (x – 5) u = (x
Pachacha [2.7K]
6(x+5)² + 5(x+5)-4 = 0

(x+5)(x+5) = x(x+5)+5(x+5) = x² + 5x + 5x + 25 = x² + 10x + 25

6(x²+10x+25) + 5(x+5) - 4 = 0
6x² + 60x + 150 + 5x + 25 - 4 = 0
6x² + 60x + 5x + 150 + 25 - 4 = 0
6x² + 65x + 171 = 0

<span>u = (x + 5)</span>
5 0
3 years ago
Find the product of the solutions
irina1246 [14]

Answer:

A.  -41/15.

Step-by-step explanation:

15x^2 + 23x - 41 = 0

Product of the roots of ax^2 + bx + c = c/a.

Thus the product of the roots of this equation = -41/15.

7 0
3 years ago
1.<br> Work<br> 8m + 5 = 6m + 17<br> Reason<br> Given Statement
snow_tiger [21]

Answer:

m = 6

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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