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soldi70 [24.7K]
3 years ago
14

WORTH 50 POINTS graph y=4/7x−2​. i need two points

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0
Cant really show you how to do it but the graph would start at the y axis at (0,-2) then from there each point would move to the left 4 and up 7 or back 4 and down 7. It would form a straight line.
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The power generated by an electrical circuit (in watts) as a function of its current ccc (in amperes) is modeled by: P(c)=-12c^2
g100num [7]

Answer:

5 amperes will produce the maximum power of 300 watts.

Step-by-step explanation:

The general form of a quadratic function presents the function in the form

f(x)=ax^2+bx+c

The vertex of a quadratic function is the highest or lowest point, also known as the maximum or minimum of a quadratic function.

We can define the vertex by doing the following:

  • Identify a, b, and c
  • Find, the x-coordinate of the vertex, by substituting a and b into

x-coordinate =-\frac{b}{2a}

  • Find, the y-coordinate of the vertex, by evaluating

y-coordinate =f(x-coordinate )=f(-\frac{b}{2a} )

We know that the power generated by an electrical circuit is modeled by

P(c)=-12c^{2}+120c

This function is a quadratic function.

To find the current that produce the maximum power you must

  • Identify a and b

a = -12 and b = 120

  • Find, the maximum current of the vertex, by substituting a and b into

maximum-current =-\frac{b}{2a}

maximum-current =-\frac{120}{2(-12)}\\\\maximum-current = 5

  • Find, the maximum-power, by evaluating

maximum-power =P(maximum-current)=P(-\frac{b}{2a} )

P(5)=-12(5)^{2}+120(5)=300

5 amperes will produce the maximum power of 300 watts.

We can check our work with the graph of the function P(c)=-12c^{2}+120c and see that the maximum is (5, 300).

5 0
4 years ago
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