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3 years ago

What is the answer to 10 ÷ 10 in decimal form

Mathematics

1 answer:

Alexus [3.1K]3 years ago

6 0

10/10 = 1

There is no decimal form unless you do 1.0, 1.00, 1.000, and so on.

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Can someone show me how to do this?

andriy [413]

3/4 ( (-50+2)/5)
= 3/4 ( -48/5)
= 3/4 * -48/5
= -36/5

6 0

3 years ago

What is the value of x? enter your answer in the box. x =

leonid [27]

Answer:

Step-by-step explanation:

Sum of all angles of triangle = 180

39 + 102 + x = 180

141 + x = 180

Subtract 141 from both sides

x = 180 - 141

x = 39

4 0

3 years ago

How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%

blondinia [14]

The trick is to exploit the difference of squares formula,

$a^2-b^2=(a-b)(a+b)$

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

$(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2$

Whatever you do to the denominator, you have to do to the numerator too. So

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2$

Expand the numerator:

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}$

So we have

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2$

But √12 = √(3•4) = 2√3, so

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}$

7 0

3 years ago

The weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a s

Evgen [1.6K]

Answer:

209.005 gms

Step-by-step explanation:

Given that the weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a standard deviation of 3 grams.

Let X be the weight of packets of cookies produced by manufacturer

X is N(202, 3) gms.

To find the weight that should be stamped on the packet so that only 1% of the packets are underweight

i.e. P(X<c) <0.01

From std normal table we find that z value = 2.335

Corresponding x value = 202+3(2.335)

=209.005 gms.

5 0

3 years ago

You downloaded a video game to your computer. You have a 60-minute free trial of the game. It takes 5 minutes to set up the game

Luba_88 [7]

Answer:

I think the equation is 7l +5=60

Step-by-step explanation:

7 0

4 years ago