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andrew-mc [135]
1 year ago
12

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

Mathematics
1 answer:
GarryVolchara [31]1 year ago
8 0

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

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Step-by-step explanation:

To sue a linear equation to solve the given problem, we must assign a function to the score of one of them. Let the score of Azmah be N. Then given that Azmah scored 17 marks more than Yazid, Yazid's score will be

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A cylinder has a volume of 140 x cubic meters and a height of 14 meters. What is the area of the base?
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Bob and Mark talk about their families. Bob says he has 3 kids, the product of their ages is 72. He gives another clue: the sum
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Not this riddle again


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what you are supposed to do is factor 72 and see their sums
1+1+72=74
1+2+36=39
1+3+24=28
1+4+18=23
2+2+18=22
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notice that all the sums are different except for the 2 that add to 14
since there is not enough info, we can conclude that the sum was 14 and that the ages is either 2,6,6 or 3,3,8
after he says, "the youngest is called justice"
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it cannot be 3,3,8 because 3 and 3 are both youngest
therefor the ages are
2,6 and 6 years old
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