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andrew-mc [135]
2 years ago
12

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

Mathematics
1 answer:
GarryVolchara [31]2 years ago
8 0

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

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Pls help pls help me<br><br><br><br><br><br> Compare the following 2/-3, -4/5, 21/-32, -15/24
mote1985 [20]

Step-by-step explanation:

to compare them, we should all bring to the same denominator.

the lcm (lowest common multiplier) is the that denominator.

let's use the approach of the prime factors :

3 : 3

5 : 5

32 : 2×2×2×2×2

24 : 2×2×2×3

the lcm is the combination of the longest "streaks" of the prime factors.

so,

2×2×2×2×2 × 3 × 5 = 32×15 = 480

2/-3 = -2/3 = -320/480 (as 3×160 = 480)

-4/5 = -4×96 / 5×96 = -384/480 (as 5×96 = 480)

21/-32 = -21/32 = -315/480 (as 32×15 = 480)

-15/24 = -15×20 / 24×20 = -300/480 (24×20 = 480)

as

-384/480 < -320/480 < -315/480 < -300/480

we can say

-4/5 < -2/3 < -21/32 < -15/24

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3 years ago
Really Easy, Help pleaseee
Dima020 [189]

1 minute = 0.25km

Step-by-step explanation:

divide both numbers that were given by 8. 8÷8 is 1 and 2÷8 is 0.25.

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Sari did not use the greatest common factor in the equation.
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Caleb went to the grocery store to purchase hamburger meat and hamburger buns for an upcoming barbecue with his friends. At the
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About $0.75 per person.



First, let’s find the cost for each portion of hamburger meat and the cost for each bun.

We can do this for the meat by doing 1.49/4 to get 0.3725.

Now we can do the same with the buns by doing 2.99/8 to get 0.37375.

Now just add these together. 0.3725+0.37375 is 0.74625, which can be rounded to $0.75.

The cost per person is approximately $0.75.



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Answer:

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