First take your whole number which is 6, then your decimals so it would be 6 1/3 but with a fraction sign 6 would go outside, 1 would go on top of 3.
Y=20x+b use a caculator to check the numbers you can use to fill in the missing numbers take your time !!
Answer:
The answer to the question is;
Then the apparent height of each pole if the tallest pole is 50 feet tall and there is 100 feet between each pole is .
Step-by-step explanation:
To answer the question we have
Let the location of the closest pole = x
Let the height of the closest pole = h feet
Also let the actual height of the pole at location 100×n feet away be 50 feet
Where n = 1, 2, 3, ...∞
Then we have by taking tangent of the similar triangles so formed by the poles
Then h/x = 50/(x +100·n)
Therefore h = 50 × x/(x +100·n) = 50·x ÷(x + 100·n) = feet
The apparent height of each pole if the tallest pole is 50 feet tall and there is 100 feet between each pole is 50·x /(x+100·n) where n is the number of 100 feet further away the pole is e.g when n = 1 we have
h = 50·x /(x+100·1) = 50·x /(x+100)
Answer:
60
Step-by-step explanation:
60*10=600
Hello from MrBillDoesMath!
Answer:
x = 140
Discussion:
Please clarify! It appears from the diagram that x + 40 = 180 (nothing to do with parallel lines). Then
x + 40 = 180 => subtract 40 from each side
x + 40 - 40 = 180 -40
x = 140
I doubt this is what was meant. I will update this answer if you provide more info.
BTW: y = 40 degrees as alternate interior angles created by a transversal cutting parallel lines are equal.
Thank you,
MrB