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laiz [17]
3 years ago
13

Select the equation that most accurately depicts the word problem. Jim weighs 30 pounds less than Tom, and together they weigh 2

10 pounds. Let n = Tom's weight in pounds.
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0
 <span>n=toms weight 

(n-30)=jims weight 

and together they weigh 210 

so it would be (n - 30) + n = 210</span><span>
</span>
You might be interested in
I need help with 19. 20.21<br> My answers were<br> 19.4/96<br> 20.4/42<br> 21.2/72<br> Am I right
pashok25 [27]
19.(3/4)/(1/32)=24
20.(3/4)/(1/14)=21/2
21.(1/2)/(1/72)=36
3 0
3 years ago
Yun was trying to factor 7x^2-14x7x
disa [49]

the width of Yun's area model is 7x units or ( x-2 )units .

<u>Step-by-step explanation:</u>

Here we have , Yun was trying to factor 7x^2-14x.  He found that the greatest common factor of these terms was 7x and made an area model:  What is the width of Yun's area model. Let's find out:

We know that area of rectangle :

⇒ Area = length(width)  .........(1)

Now , According to question we have

⇒ Area = 7x^2-14x

⇒ Area = 7x(x-2)

Comparing this equation to equation (1) we get that :

⇒ width = 7x or , width =x -2

Therefore , the width of Yun's area model is 7x units or ( x-2 )units .

8 0
3 years ago
Read 2 more answers
Solve the equation.<br> 9 = 9m<br> M=_____
Schach [20]

9=9m

Next, what you want to do is divide both sides by m to get the variable.

m=1

4 0
3 years ago
A) not similar
inn [45]

Answer:

A) not similar

Step-by-step explanation:

for the triangles to be similar the side lengths must be proportional.

For example:

99/35 should be equal to 121/44 but when we do cross multiplying we see they are not equal therefore the the triangles are not similar.

5 0
2 years ago
Steve's scores on 6 of his tests were 92, 78, 86, 92, 95, and 91. If he took a seventh test and raised the mean of his scores by
monitta

Answer:

96

Step-by-step explanation:

First we need to know the mean of the Steve's scores on 6 of his tests. Given the six scores as 92, 78, 86, 92, 95, and 91.

Mean = sum of the scores/Total test taken

Mean = 92+78+86+92+95+ 91/6

Mean = 534/6

Mean = 89

If he took the seventh test and the mean score is raised by 1 them the new mean will be expressed as;

New mean = 92+78+86+92+95+ 91+x/7 = 89+1

Where x is the new score. Note that of a new score is added, the total year taken will also change to 7

To get x;

92+78+86+92+95+ 91+x/7 = 89+1

92+78+86+92+95+ 91+x/7 = 90

534+x/7 = 90

Cross multiply

533+x = 90×7

533+x = 630

x = 630-534

x = 96

Hence the score of the seventh test is 96

8 0
3 years ago
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