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blsea [12.9K]
2 years ago
8

What is 2^c=8 (please help)

Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

c=3.

Step-by-step explanation:

∵2*2*2=8,

∴2^3=8.

∵2^c=8,

∴c=3.

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Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t
inessss [21]

Step-by-step explanation:

a_1=6\\a_2=a_1+1\to a_2=6+1=7\\a_3=a_2+1\to a_3=7+1=8\\a_4=a_3+1\to a_4=8+1=9\\\vdots\\\\\text{The recursive formula}\\a_n=\left\{\begin{array}{ccc}a_1=6\\a_n=a_{n-1}+1\end{array}\right\\\\\text{It's an arithmetic sequence with}\ a_1=6\ \text{and difference}\ d=1\\\\\text{The explicit formula of an arithmetic sequence:}\\\\a_n=a_1+(n-1)d\\\\\text{Substitute:}\\\\a_n=6+(n-1)(1)\\a_n=6+n-1\\a_n=5+n\\\\a_n=n+5

5 0
3 years ago
(geomatry) Pleasee help I'll give brainest and thanks :)
lord [1]

Answer:

JML=142 degrees

Step-by-step explanation:

This shape is a rhombus, as all 4 sides are equal, but the angle measures are not. One of the properties of a rhombus is that opposite angles are congruent, and adjacent angles are supplementary. Only the second one is important. Since angles KLM and angle JML are supplementary, the equation KLM+JML=180 can be used. KLM is then substituted by the given angle measure, 38 degrees, to get an equation such as JML+38=180. Now, to solve for JML, 38 must be subtracted from both sides of the equation, which leaves teh answer of JML=142.

7 0
3 years ago
Read 2 more answers
Please help pls pls help pls belp
Delvig [45]

Answer:

After 1 second, the ball will reach a maximum height of 16 feet

Step-by-step explanation:

The height of the ball after t seconds: h(t) = -16t^2 + 32t

The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola

t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second

then

h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16

After 1 second, the ball will reach a maximum height of 16 feet

8 0
2 years ago
A building with a height of 14 m casts a shadow that is 16 m long while a taller building casts a 24 m long shadow. What is the
uranmaximum [27]
26 i am not really sure cuz what i did was 16-14= 2 
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5 0
3 years ago
Read 2 more answers
Does anybody know this? I appreciate any help. I ONLY need help with 6c.
elena55 [62]

40:68.6

Hoped it helps

8 0
3 years ago
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