The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%.
16% = 0.16
1/6 = 0.16666
1.6x10^6 = 1600000
0.166 = 0.166
order from greatest to least:
1.6x10^6, 1/6, 0.166, 16%
Answer is D
13x + 13 + 2x = 2
15x + 13 = 2
15x = -11
For 11a its 2:10 because how you would come up with it is by placing pablos free minutes first and then putting pablos paid minutes and 11b is8:25 because once again you would place sams free minutes first and then his paid minutes
<em>Your answer will be, </em><em>"6p - 8"</em>
Thanks,
<em>Deku ❤</em>
