Answer:
slope: 5/2
Step-by-step explanation:
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
Exact answer is 0.00076232
Step-by-step explanation:
i can give give u a website that does this, if u want
Only one section should be coloured in because it's 1/8 of the spinner. Meaning, there is one chance of landing on any colour.
Answer:
Looks good to me
Step-by-step explanation:
I checked for an incorrect answer and it seems like you got everything right :)