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Alex17521 [72]
2 years ago
7

Suppose that you are interested in determining the average height of a person in a large city. You begin by collecting the heigh

ts of a random sample of 256 people from the city. The average height of your sample is 64 inches, while the standard deviation of the heights in your sample is 4 inches.The standard error of your estimate of the average height in the city is .
Mathematics
1 answer:
monitta2 years ago
5 0

The standard error of the estimate of average height in the city is 0.25.

Given average height 64 inches, sample mean and sample standard deviation of 4 inches.

We have to determine the standard error of the estimate of the average height in the city.

Standard error is the error which is predicted before research to happen in research. It is calculated by dividing the standard deviation of the sample by the square root of the sample size.

n=256

μ=mean

s = sample standard deviation

Standard error=s/\sqrt{n}

=4/\sqrt{256}

=4/16

=0.25

Hence the standard error of the estimate of the average height is 0.25.

Learn more about standard error at brainly.com/question/1191244

#SPJ4

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Consider the following hypothesis test: H0: LaTeX: \mu_1-\mu_2=0μ 1 − μ 2 = 0 Ha: LaTeX: \mu_1-\mu_2\ne0μ 1 − μ 2 ≠ 0 The follow
Pavel [41]

Answer:

z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53

Step-by-step explanation:

Data given and notation

\bar X_{1}=104 represent the mean for the sample 1

\bar X_{2}=106 represent the mean for the sample 2

\sigma_{1} =8.4 represent the population standard deviation for the sample 1

\sigma_{2}=7.6 represent the population standard deviation for the sample 2

n_{1}=80 sample size for the group 1

n_{2}=70 sample size for the group 2

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0:\mu_{1}-\mu_{2} =0

H1:\mu_{1} -\mu_{2} \neq 0

If we analyze the size for the samples both are greater than 30 and we know the population deviations so for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

First we need to calculate the mean and deviation for each sample, after apply the formulas (2) and (3) we got the following results:

And with this we can replace in formula (1) like this:

z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53

7 0
3 years ago
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soldier1979 [14.2K]
2,3,5,7,13,15,23,and 61 are all prime
5 0
3 years ago
HELP ME PLEASE!
Sav [38]

Answer:

There are 60 lemon cookies.

Step-by-step explanation:

1/2/240=120

3/20/240=36

1/10/240=24

120+36+24=180

240-180=60

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Answer:

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Theres not enough information in the question

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