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Drupady [299]
2 years ago
12

A water sample has a pH 10 and contains 56 mg/L HCO3- and 32 mg/L CO32-. Calculate the alkalinity in mg/L as CaCO3.

Biology
1 answer:
Greeley [361]2 years ago
5 0

The alkalinity as CaCO3 in mg/L is 108,23

<h3>What is alkalinity?</h3>

Alkalinity is the total measure of substances present in water, capable of neutralizing acids. In other words, it is the amount of substances present in the water that act as a buffer.

With that being said;

Equivalent weight = {molar mass}*{ion charge/oxidation number}

  • Molar mass of HCO3- = 61g/mol
  • Molar mass of CO3 = 60g/mol
  • Molar mass of CaCO3 = 100g/mol

  • Eq. cot. of HCO3- = 61g/Eq
  • Eq. cot. of CO3 = 30g/Eq
  • Eq. cot. of CaCO3 = 50g/Eq

Alkalinity due to CO3 = {32x50}{30} = 53.33mg/L

Alkalinity due to HCO3- = {56x50}{61} = 54,90mg/L

Total Alkalinity = 53,33 + 54,90 = 108,23 mg/L

In this case, we have to The alkalinity as CaCO3 in mg/L is 108,23 mg/L

See more about pH at: brainly.com/question/15289741

#SPJ1

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