The two linear equations in two variable is:
12 x + 3 y = 40
7 x - 4 y = 38
(a) For a system of equations in two Variable
a x + by = c
p x + q y = r
It will have unique solution , when
![\frac{a}{p}\neq \frac{b}{q}\neq\frac{c}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bp%7D%5Cneq%20%5Cfrac%7Bb%7D%7Bq%7D%5Cneq%5Cfrac%7Bc%7D%7Br%7D)
As, you can see that in the two equation Provided above
![\frac{12}{7}\neq \frac{3}{-4}\neq \frac{40}{38}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B7%7D%5Cneq%20%5Cfrac%7B3%7D%7B-4%7D%5Cneq%20%5Cfrac%7B40%7D%7B38%7D)
So, we can say the system of equation given here has unique solution.
(b). If point (2.5, -3.4) satisfies both the equations, then it will be solution of the system of equation, otherwise not.
1. 12 x+3 y=40
2. 7 x-4 y=38
Substituting , x= 2.5 , and y= -3.4 in equation (1) and (2),
L.H.S of Equation (1)= 1 2 × 2.5 + 3 × (-3.4)
= 30 -10.20
= 19.80≠ R.H.S that is 40.
Similarly, L H S of equation (2)= 7 × (2.5) - 4 × (-3.4)
= 17.5 +13.6
= 31.1≠R HS that is 38
So, you can Write with 100 % confidence that point (2.5, -3.4) is not a solution of this system of the equation.