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8090 [49]
2 years ago
12

Anybody know the answer to number 2 !!!

Mathematics
1 answer:
MrRa [10]2 years ago
5 0

Answer:

Well I can't put it on a number line but the order they should go in is: 2 \frac{1}{4}, 2.3 (repeating), 2.5,\sqrt{8}

Step-by-step explanation:

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Help me please. i've tried this so many times, writing it out, calculator. nothing's worked
likoan [24]

Answer:

-27

Step-by-step explanation:

y7 + 4x

(-1)7 + 4(-5)

-7 + (-20)

-27

8 0
3 years ago
What is 1/2 Of 2/2 use fractions
damaskus [11]

Answer:

Step-by-step explanation:

yes

5 0
3 years ago
Read 2 more answers
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
If VUW is equiangular, find k and t.
Alenkinab [10]

Answer:

C. k=68, t=52

Step-by-step explanation:

Let u, v, y represent the measures of the unmarked angles at the respective vertices. The angles of the equiangular triangle are all 180°/3 = 60°, so we have the relations ...

  • y=v
  • y+v+k = 180
  • v+64+60 = 180
  • u=64
  • u+64+t = 180

From these relations, we know that

... v = 180 -124 = 56 . . . . . 3rd equation above

... 56 +56 +k = 180 . . . . . . 2nd equation above, with y=v=56

... k = 180 -112 = 68 . . . . . above with 112 subtracted

... t = 180 -128 = 52 . . . . . 5th equation above with u=64 and 128 subtracted

8 0
4 years ago
Read 2 more answers
I need help with this
andrey2020 [161]
18a:16 18b:32 % means out of 100
3 0
3 years ago
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