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3 years ago

9/15 is equal to what

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

3 0

9/15 is equal to 3/5

9/3 = 3

15/3 = 5

So your answer is 3/5.

Hope this Helps!!

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A company launches 4 new products. The market price, in dollars, of the 4 products after a different number of years, x, is show

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Product 4 after the third year is 27 which is higher than the rest after 3 years.

And because x is raised to the third, the amount would Increase by being raised to the 3rd every year.

The answer is Product 4.

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3 years ago

A salesperson earned a salary of $12000 per year plus 5% commission on sales of $100000. What is his total income

Papessa [141]

If im doing right....

100,000*.5=50,000

Then 12,000+50,000=62,000 per year.

-Seth

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3 years ago

Read 2 more answers

What is the approximate volume of the cone? use 3.14 for

Natali5045456 [20]

Answer:

157 cm²

Step-by-step explanation:

volume = (1/3) * π * r² * h

volume = (1/3) * π * 5² * 6

volume = (1/3) * π * 25 * 6

volume = (1/3) * π * 150

volume = (1/3) * 471

volume = 157 cm²

8 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

Put the expression (48c)^3/4 in radical form hurry plz

Svet_ta [14]

Remember that if something is raised to a fraction exponent, the denominator of the fraction is the radical and the numerator stays a power. So it becomes:

fourth root of (48c)^3

Hope this helps

8 0

3 years ago