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erma4kov [3.2K]
2 years ago
12

Find the h.c.f of {x}^{3} + {y}^{3} \: and \: \: {x}^{2} - xy + {y}^{2}x 3 +y 3 andx 2 −xy+y 2 ​

Mathematics
1 answer:
Ahat [919]2 years ago
5 0

Factorize the sum of cubes:

x^3 + y^3 = (x+y) (x^2 - xy + y^2)

so x^2-xy+y^2 is a factor of x^3+y^3. Then the HCF is \boxed{x^2 - xy + y^2}.

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Answer:

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Operate:

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yx-2x=-3-4+2y

Factor the left side and operate on the right side:

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Solve for x:

\displaystyle x=\frac{-7+2y}{y-2}

Interchange variables:

\displaystyle y=\frac{-7+2x}{x-2}

Call y as the inverse function:

\boxed{\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}}

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