Alll of the follow are true except option 4, which states the absolute value of -93 is -93. This is not true! Absolute value will always be positive.

Hope this helps!

7 0

4 years ago

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In ΔVWX, the measure of ∠X=90°, XW = 36, WV = 85, and VX = 77. What ratio represents the sine of ∠W?

eimsori [14]

<u>Given</u>:

In ΔVWX, the measure of ∠X=90°, XW = 36, WV = 85, and VX = 77.

We need to determine the ratio that represents the sine of ∠W

<u>Ratio of sin of ∠W:</u>

The ratio of sin of ∠W can be determined using the trigonometric ratios.

The ratio of $sin \ \theta$ is given by

$sin \ \theta=\frac{opp}{hyp}$

From the attached figure, the opposite side of ∠W is XV and the hypotenuse of ∠W is WV.

Hence, substituting in the above ratio, we get;

$sin \ W=\frac{XV}{WV}$

Substituting the values, we get;

$sin \ W=\frac{77}{85}$

Thus, the ratio of sine of ∠W is $sin \ W=\frac{77}{85}$

6 0

3 years ago

Find the values of A and B<br> PLEASE HELP GIVING BRAINLIEST

erastovalidia [21]

Factoring the roots, the values of A and B are given as follows:

A = 3z.

B = 2.

<h3>What are the values of A and B?</h3>

The expression is:

$\sqrt{\frac{45\alpha z^3}{40y}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}$

We have that:

$\frac{45}{40} = \frac{9}{8}$

Hence:

$\sqrt{\frac{45\alpha z^3}{40y}} = \sqrt{\frac{9\alpha z^3}{8}} = \sqrt{\frac{9\alpha z^2 \times z}{4 \times 2}} = \frac{A\sqrt{\alpha z}}{B\sqrt{2y}}$

Hence, comparing the last two equalities:

A = 3z.

B = 2.

More can be learned about the factoring of roots at brainly.com/question/24380382

#SPJ1

7 0

2 years ago