Since there are 8 students, each student gets 1/8 of the available cake. Since there is 3/4 of a cake available, they will get 1/8 of 3/4.
Source: https://www.wyzant.com/resources/answers/142015/there_are_8_students_in_a_group_and_3_4_cake_how_much_cake_will_each_student_get_if_divided_evenly
Answer: the answer is 5
Step-by-step explanation:
Done this before
Answer: See explanation
Step-by-step explanation:
Point slope form: y - y₁ = m (x - x₁)
y₁ = 6
x₁ = -7
y - 6 = -1 (x - [-7])
y - 6 = -1 (x + 7)
y - 6 = -1x - 7
Add 6 to both sides
y = -1x - 1 <em>or </em>y = -x -1
Slope intercept form: y = mx + b
m = -1
b = 6
y = -1x + 6 <em>or </em>y = -x + 6
Standard form: Ax + By = C
Change slope intercept form into _x + _y = c
Slope intercept form: y = -x + 6
Standard form:
y = -x + 6
Add x to both sides
x + y = 6 <em>or </em>-x - y = -6
Hope I helped!
Answer:
joint variation means L (safe load) is directly proportional to both w and d2
inverse proportionality means L = k/l
So the equation is:
L = k(wd2/l)
You are given:
w = 6 in
d = 5 in
l = 12 ft
L = 7666 lbs
7666 = k(6*52/12)
Solve for the constant, k.
7666 = k (6*25/12)
7666 = k (150/12)
7666 = k (12.5)
613.28 lbs/(ft.in3) = k
Use this k-value to solve for L in the last part of the question.
What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)
w = 3 in
d =7 in
l = 15 ft
k = 613.28 lbs/(ft.in3)
Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro