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Vikentia [17]
2 years ago
12

A company has six employees.The salary of five of the employees are P2200,P1300,P800,P940 and P560.When the sixth employee is in

cluded,the total monthly salaries of the employees becomes P7000.
Calculate the salary of the sixth employees








The company is joined by two more employees whose salaries are of equal amounts.The mean salary of all 8 employees is P1100
Calculate the monthly salary of each of the new employees​
Mathematics
1 answer:
Dafna1 [17]2 years ago
3 0

Answer:

First answer is 1200

Second answer is 900 for each new employee

Step-by-step explanation:

First answer:

2200+1300+800+940+560+x = 7000

5800+x = 7000 subtract 5800 from both sides and you get your answer

x = 1200

Second answer:

x = 900.  Each of the two employees made 900 a month or 1800 a month for both of them.

To find the average we take the total salaries and divide by the number of people to find the average salary.  In this case, we know the average and we know all of the salaries, but two.  We can figure this out.

(7000 + 2x)/8 = 1100  multiple both sides by 8 to clear the fraction/

7000 +2x = 8800  Subtract both sides by 7000

2x = 1800  Divide both sides by 2

x = 900

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A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
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Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

                           = \frac{12!}{(3!)^{4}   }×\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = \frac{479,001,600}{(6)^{4}   }×\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}

                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0
3 years ago
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