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svet-max [94.6K]
3 years ago
15

Let P(x) denote the statement "2x+5 > 10." Which of the following is true?

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0

Answer: P(3) is True

Step-by-step explanation:

The given statement is an inequality denoted as P(x). To find out which of the options is true you have to evaluate each given value of X in the inequality and perform the arithmetic operations, then you have to see if the expression makes sense.

For P(0): Replace X=0 in 2x+5>10

2(0)+5>10

0+5>10

5>10 is false because 5 is not greater than 10

For P(3): Replace X=3 in 2x+5>10

2(3)+5>10

6+5>10

11>10 is true because 11 is greater than 10

For P(2): Replace X=2 in 2x+5>10

2(2)+5>10

4+5>10

9>10 is false

For P(1): Replace X=1 in 2x+5>10

2(1)+5>10

2+5>10

7>10 is false

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X=14

Step-by-step explanation:

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3 years ago
Decide whether the change is an increase or a decrease, and find the percent change. Original number = 35; New number = 16.... P
Elodia [21]

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3 0
3 years ago
The average of four different positive integers is 9. What is the greatest value for one of the integers?
saul85 [17]

From the given information; Let the unknown different positive integers be (a, b, c and d).

An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.

Suppose we make an assumption that (a) should be the greatest value of this integer.

Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.

Therefore, the average of this integers = 9

Mathematically;

\mathbf{\dfrac{(a+b+c+d)}{4} =9}

\mathbf{\dfrac{(a+1+2+3)}{4} =9}

\mathbf{\dfrac{(6+a)}{4} =9}

By cross multiplying;

6+a = 9 × 4

6+a = 36

a = 36 - 6

a = 30

Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.

Learn more about integers here:

brainly.com/question/15276410?referrer=searchResults

8 0
3 years ago
Read 2 more answers
Helpppppppppppppppppp​
pochemuha

Answer:

what do you need help with ???

4 0
3 years ago
For what values of (m) does the graph of y=mx²-5x-2 have no x-intercepts?
Natali5045456 [20]
You need to find where the discriminant is less than zero
Remember the discriminant is b^2 - 4ac
a = m
b = -5
c = -2
Set up the inequality like this
(-5)^2 - 4m(-2) < 0
25 + 8m < 0
8m < -25
m < -25/8 < -3.125

So any number less than -3.125 will make this graph have no x-intercepts (or real roots)
5 0
3 years ago
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