Suppose you have a right triangle with congruent legs and a hypotenuse that measure (12sqrt(5))/5 What is the length of the smal
ler leg? Round to the nearest hundredth
1 answer:
The length of the smaller leg is 3.79
<h3>How to determine the length of the smaller leg?</h3>Represent the smaller leg with x.
So, we have:
-- Pythagoras theorem
This gives
2x^2 = 144/5
Divide by 2
x^2 = 72/5
This gives
x^2 = 14.4
Take the square root
x = 3.79
Hence, the length of the smaller leg is 3.79
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Answer:
a)This solution matches with the original equation and its solution
b)This solution matches with the original equation and its solution
c)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
d)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
Step-by-step explanation:
i) Which scenarios can be solved by 1.5x + 2.25 = 12.75. Select all that apply and note the given solution.
therefore 1.5x = 10.5 therefore x = 7
a) let the number be x
therefore if then the number x = 7.
This solution matches with the original equation and its solution
b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the
number of mile = x, then the number of miles Juan can ride the taxi for
$12.75 is x = 7.
This solution matches with the original equation and its solution
c)if nine quarters of a number, say x, increased by three halves is fifty one
quarters, the number is x = 5,
This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.
d.) If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the
number of mile = x, then the number of miles Juan can ride the taxi for
$12.75 is x = 5.
This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.