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mariarad [96]
2 years ago
5

Suppose you have a right triangle with congruent legs and a hypotenuse that measure (12sqrt(5))/5 What is the length of the smal

ler leg? Round to the nearest hundredth

Mathematics
1 answer:
anastassius [24]2 years ago
4 0

The length of the smaller leg is 3.79

<h3>How to determine the length of the smaller leg?</h3>

Represent the smaller leg with x.

So, we have:

x^2 + x^2 = ((12\sqrt5)/5)^2 -- Pythagoras theorem

This gives

2x^2 = 144/5

Divide by 2

x^2 = 72/5

This gives

x^2 = 14.4

Take the square root

x = 3.79

Hence, the length of the smaller leg is 3.79

Read more about right triangles at

brainly.com/question/6322314

#SPJ1

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Please answer fast, I need great answers!!!!! This is mathematics.
Fantom [35]
20, 25, 30, 30, 31, 40, 41, 49
median = 30.5

lower IQR = 27.5
upper IQR = 40.5

Range IQR = 40.5 - 27.5 = 13

answer is 13
7 0
3 years ago
Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
3 years ago
Find the simplified product. 2V5x^3(-3/10x^2)
mariarad [96]

Answer:

Step-by-step explanation:

4 0
3 years ago
in a circle a 60 sector has an area of 25 pi square feet. what is the circumference? leave your answer in terms of pi and in sim
belka [17]
The area of the sector is given by the equation,
                           A = πr²(x / 360°)
where x is the number of degrees in the figure. 
                           25π ft² = (πr²)(60/360)
The value of  r is 12.25 ft. Then, we use this value to calculate for the circumference of the sector. 
                           C = 2πr(x/360)
Substituting,
                              C = 2π(12.45)(60/360)
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7 0
3 years ago
Find the volume in the pyramid
lilavasa [31]

Answer:

900 ft!

Step-by-step explanation:

Volume = l ∗ w ∗ h

5 0
3 years ago
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