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julsineya [31]
3 years ago
15

A large aquarium has one tank holds 41,253 gallons of water and another tank that holds 62,965 gallons of water . How many total

gallons of water are there?
Mathematics
2 answers:
Ivanshal [37]3 years ago
6 0
You would just need to add the two:

41,253+62,965=104,218
Marina CMI [18]3 years ago
5 0
104218 this is the answer
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Step-by-step explanation:

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Answer:

b.(-2, -1), (3, 4)

Step-by-step explanation:

We are given function as

f(x)=x^4-3x^3-2x^2+3x-5

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At (-6,-5):

Firstly we will plug x=-6

f(-6)=(-6)^4-3(-6)^3-2(-6)^2+3(-6)-5=1849

now, we can plug x=-5

f(-5)=(-5)^4-3(-5)^3-2(-5)^2+3(-5)-5=930

since, both are positive values

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At (-4,-3):

Firstly we will plug x=-4

f(-4)=(-4)^4-3(-4)^3-2(-4)^2+3(-4)-5=399

now, we can plug x=-3

f(-3)=(-3)^4-3(-3)^3-2(-3)^2+3(-3)-5=130

since, both are positive values

So, zeros can not lie between them

At (-2,-1):

Firstly we will plug x=-2

f(-2)=(-2)^4-3(-2)^3-2(-2)^2+3(-2)-5=21

now, we can plug x=-1

f(-1)=(-1)^4-3(-1)^3-2(-1)^2+3(-1)-5=-6

since, one is positive and another is negative

So, zeros will lie between them

At (3,4):

Firstly we will plug x=3

f(3)=(3)^4-3(3)^3-2(3)^2+3(3)-5=-14

now, we can plug x=4

f(4)=(4)^4-3(4)^3-2(4)^2+3(4)-5=39

since, one is positive and another is negative

So, zeros will lie between them

zeros will be between

(-2, -1), (3, 4)

5 0
3 years ago
Read 2 more answers
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