THE AVERAGE RATE CHANGE OF F IS SLOWER THAN THE AVERAGE RATE OF CHANGE OF G OVER INTERVAL [0,2]
Answer:
16 liters
Step-by-step explanation:
40 liters ÷ 30 mins = 1.333333... liters
1.3333333... liters x 12 mins = 16
I would say the best option is A.HL
Answer:
9.99 years
Step-by-step explanation:
P=$3,500
r=7%=0.07
n=4(quarterly)
A= double of $3,500=
$3,500×2=$7,000
t=?
A=p(1+r/n)^nt
$7,000=$3,500(1+0.07/4)^4t
$7,000=$3,500(1+0.0175)^4t
$7,000=$3,500(1.0175)^4t
Divide both sides by $3,500
2=(1.0175)^4t
Take the log to base 10 of both sides
log2=4t × log1.0175
0.30103=4t × 0.00753
0.30103=4(0.00753)t
0.30103=0.03012t
t=0.30103/0.03012
t=9.99435
Approximately
9.99 years
Answer:
1
Step-by-step explanation:
if it's above 1.5 you would round up but it's not so